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Stopping Potential vs Frequency

In a photoele...

Question

In a photoelectric experiment, the potential difference V that must be maintained between the illuminated surface and the collector so as just prevent any electron from reaching the collector is determined at different frequencies f of the incident illumination. Graph obtained is shown in the figure. The maximum KE of the electrons emitted at frequency $f_{1}$ is

A

h f_{1}

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B

\frac{v_{1}}{f_{1} - f_{0}}

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C

h (f_{1} - f_{0})

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D

e V_{1} (f_{1} - f_{0})

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Solution

The correct option is C $h (f_{1} - f_{0})$
$K_{m a x} = h f_{1} - ϕ_{0} = h f_{1} - h f_{0} = h (f_{1} - f_{0})$

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