In a photoelectric experiment, the stopping potential $V_{s}$ is plotted against the frequency $v$ of incident light. The resulting curve is a straight line which makes an angle $θ$ which is equal to ( $φ$ = work function of surface)

h / e

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e / h

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- \frac{φ}{3}

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\frac{e h}{φ}

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Solution

The correct option is A $h / e$
We know that $e V_{s} = h ν - ϕ = V_{s} = \frac{h ν}{e} - \frac{ϕ}{e}$
by comparing above equation with $y = m x + c$ :straight line equation
we get, $m = s l o p e = \frac{h}{e}$

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In a photoelectric experiment, the stopping potential Vs is plotted against the frequency v of incident light. The resulting curve is a straight line which makes an angle θ which is equal to (φ= work function of surface)

The correct option is A h/eWe know that eVs=hν−ϕ=Vs=hνe−ϕeby comparing above equation with y=mx+c :straight line equationwe get, m=slope=he

In a photoelectric experiment, the stopping potential $V_{s}$ is plotted against the frequency $v$ of incident light. The resulting curve is a straight line which makes an angle $θ$ which is equal to ( $φ$ = work function of surface)

The correct option is A $h / e$
We know that $e V_{s} = h ν - ϕ = V_{s} = \frac{h ν}{e} - \frac{ϕ}{e}$
by comparing above equation with $y = m x + c$ :straight line equation
we get, $m = s l o p e = \frac{h}{e}$