wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a photoelectric experiment, the wavelength of the light incident on a metal is changed from 300nm to 400nm. The decrease in the stopping potential is close to: (hce=1240nmV)

A
0.5V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.0V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2.0V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.5V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1.0V
hcλ1=ϕ+eV1 .(i)
hcλ2=ϕ+eV2 (ii)
(i)-(ii)
hc(1λ11λ2)=e(V1V2)
V1V2=hce(λ2λ1λ1λ2)
=(1240nmV)100nm300nm×400nm
=1V.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
I vs V - Varying Intensity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon