In a pipe open at both ends distance between node and antinodes is:
A
λ/4
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B
λ/2
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C
3λ/4
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D
none of the above
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Solution
The correct option is Aλ/4 In a standing wave , the distance between two successive nodes or antinodes is λ/2 , as standing waves are produced in an organ pipe and between two successive nodes , we have an antinode or between two successive antinodes , a node is present .
Therefore distance between a node and antinode will be λ/4 .