CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a pipe open at both ends distance between node and antinodes is:

A
λ/4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
λ/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3λ/4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A λ/4
In a standing wave , the distance between two successive nodes or antinodes is λ/2 , as standing waves are produced in an organ pipe and between two successive nodes , we have an antinode or between two successive antinodes , a node is present .
Therefore distance between a node and antinode will be λ/4 .

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Wavefronts
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon