Question

In a planar tetra-atomic molecule $X{Y}_3$, X is at the centroid of the equilateral triangle formed by the atoms, Y. If the X - Y bond distance is $1A^{\circ }$, what is the distance between the centres of any two y atoms?

• A. $\frac{1}{\sqrt{3}}{A}^{\circ }$
• B. $\sqrt{2}{A}^{\circ }$
• C. $\sqrt{3}{A}^{\circ }$
• D. $\frac{1}{\sqrt{2}}{A}^{\circ }$

Answer 1

The correct option is C $\sqrt{3}{A}^{\circ }$



$\frac{BE}{BC}=cos{30}^{\circ }=\frac{\sqrt{3}}{2}$
Distance between the centres of two B atoms = $2\times BE=\sqrt{3}{A}^{\circ }$