Question

In a plane of electromagnetic wave, the electric field (E) having amplitude of 48 Vm^​-1 oscillates at a frequency of 2*10¹⁰Hz . the amplitude of oscillating magnetic field B is ?

Answer 1

$$\begin{gathered} Theamplitudeofthemagneticfieldis \\ {B}_0=E/C_0 \\ where{C}_{0}isthespeedoflightinvaccum=3\times {10}^{8}m/s \\ {B}_0=\frac{48}{3\times {10}^8}=16\times {10}^{-8}T \end{gathered}$$