In a plane there are $6$ points such that no three points are collinear. How many triangles do these points determine?

2

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3

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6

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18

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20

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Solution

The correct option is E $20$
Out of $6$ points , we have to select $3$ points to form a triangle
So the number of triangles formed is ${^{6} C}_{3} = 20$

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