Question

In a polar molecule, the ionic charge is $4.8\times {10}^{-10}$ e.s.u. If the inter-ionic distance is $1\stackrel{\mathrm{o}}{\mathrm{A}}$ unit, then the dipole moment is

• A. 41.8 D
• B. 4.18 D
• C. 4.8 D
• D. 0.48 D

Answer 1

The correct option is C

4.8 D

Explanation for the correct answer:-

Option (C) 4.8 D:

Step 1: Given data

Ionic charge = $4.8\times {10}^{-10}$ e.s.u.

Ionic distance = $1\stackrel{\mathrm{o}}{\mathrm{A}}={10}^{-8}$ cm.

Step 2: Calculating the dipole moment

We know that,

$$\begin{gathered} \mathrm{Dipole}\mathrm{moment}=\mathrm{ionic}\mathrm{charge}\times \mathrm{ionic}\mathrm{distance} \\ \Rightarrow \mathrm{Dipole}\mathrm{moment}=(4.8\times {10}^{-10})\times 1\stackrel{\mathrm{o}}{\mathrm{A}} \\ \Rightarrow \mathrm{Dipole}\mathrm{moment}=(4.8\times {10}^{-10})\times {10}^{-8} \\ \Rightarrow \mathrm{Dipole}\mathrm{moment}=4.8\times {10}^{-8}\mathrm{e}.\mathrm{s}.\mathrm{u}/\mathrm{cm} \\ \Rightarrow \mathrm{Dipole}\mathrm{moment}=4.8\mathrm{D} \end{gathered}$$

Therefore, the dipole moment is option (C) 4.8 D