wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a polygon, the interior angles are in A.P. with common difference 5 and smallest angle 120, then the number of sides is :


A

9 or 16

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

16

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

25

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

9


Let number of sides of polygon = n.

∴ Sum of internal angles = 180n - 360.

∴ 180n - 360 = n2[240 + (n-1)5]

n2 - 25n + 144 = 0 ⇒ n = 16 or 9.

Since internal angle of a polygon < 180.

T16 = 120 + 15 × 5 = 195 > 180 ⇒ n ≠ 16.

Hence n = 9.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon