In a polyhedron, if the number of vertices is 8 and the number of edges is twice as the number of faces, then the number of faces and edges of the polyhedron respectively is?
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Solution
Let the number of faces F=x
The number of edges E=2x
By Euler’s formula F+V=E+2 x+8=2x+2 x=6
The number of faces =6 and the number of edges =12.