Answer is "0.6"
Total number of individuals = 1000
Genotype AA has 360 individuals i.e. the frequency of allele A in AA = 360
Genotype Aa has 480 individuals i.e. frequency of allele A in Aa = 1/2 *480 = 280
Genotype aa does not contain allele A. So frequency is zero
So total frequency of allele A =360+240/1000 = 0.6