Question

In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is

• A. 0.4
• B. 0.5
• C. 0.6
• D. 0.7

Answer 1

Answer: (C)

0.6

• According to Hardy-Weinberg equilibrium, the genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.
• Equation: p${}^2$ +2pq + q${}^2$ = 1

where,

p${}^2$ is the frequency of homozygous genotype AA

q${}^2$ is the frequency of genotype aa

2pq is the frequency of genotype Aa

• There are 1000 individuals, out of which 360 belong to genotype AA.

p${}^2$ =360/1000 = 0.36

Then p = 0.6.

So, the correct answer is '0.6'.