Question

In a population of $1000$ individuals, $360$ belong to genotype $AA$, $480$ to $Aa$ and remaining $160$ to $aa$. Based on this data, the frequency of allele $A$ in the population is

• A. $0.4$
• B. $0.7$
• C. $0.5$
• D. $0.6$

Answer 1

The correct option is D $0.6$

The Hardy-Weinberg equation used to determine genotype frequencies is:

$p^2+2pq+q^2=1$.

Where $p^2$ represents the frequency of the homozygous dominant genotype $\left(AA\right)$.

$2pq$ represents the frequency of the heterozygous genotype $\left(Aa\right)$.

$q^2$ represents the frequency of the homozygous recessive genotype$\left(aa\right)$.

There are $1000$ individuals, out of which $360$ belong to genotype $AA$.

$p^2=360/1000=0.36$
$p=\sqrt{.36}$
$=0.6$.

Hence the correct option is
b. $0.6$