Question

In a population of 1000 people, 360 belong to the AA genotype, 480 to the Aa genotype, and the remaining 160 to the aa genotype. What is the frequency of allele A in the population, based on this information?

• A. 0.5
• B. 0.7
• C. 0.6
• D. 0.4

Answer 1

The correct option is C

0.6

The correct option is C.

Explanation of correct option:

Step 1: Given data

Individuals with AA genotype = 360

Individuals with Aa genotype = 480

Individuals with aa genotype = 160

Step 2: Applying the formula

Formula Used: Frequency of allele A= $\raisebox{1ex}{$\left({\displaystyle \raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2\times Aa+$}\right.}\sqrt{AA}\right)$}\!\left/ \!\raisebox{-1ex}{$T$}\right.$

Where AA= Individuals with AA genotype, Aa = Individuals with Aa genotype, T = Total number of individuals in a population

Step 3: Solving equations to get the required value

Solving equations to get the required value :

Given AA=360, Aa= 480

Using equation (1)

Frequency of allele A= $\raisebox{1ex}{$\left({\displaystyle \frac{Aa}{2}+}AA\right)$}\!\left/ \!\raisebox{-1ex}{$T$}\right.$

Frequency = $\raisebox{1ex}{$\left({\displaystyle \frac{480}{2}+}360\right)$}\!\left/ \!\raisebox{-1ex}{$1000$}\right.$

= $\frac{600}{1000}$= 0.6

Final answer: The frequency of allele A in the population is 0.6.