In a population of 1000 individuals60 belong to genotype AA,480 belong to aa then the frequency of allele population
Given.. No.of individuals with genotype AA :60
No.of individuals with genotype aa : 480
No.of individuals with genotype Aa : 100 - (60+480) = 460
Therefore.. 460/2 = 230, It means that there are 230 individuals with A allele
Total no. Of individuals with A allele is 60+230= 290
Frequency of allele A in the population is (290÷1000)*100 = 29%