In a population of 200 organisms if only eight organisms have recessive form of character, then find out the percentage of dominant alleles of that character in population
A
20%
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B
16%
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C
96%
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D
80%
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Solution
The correct option is D80% In the given problem, the number of organisms having recessive character are 8 out of 200, that is 4%.
Frequency of homozygous recessive (q2) = 0.04.
Therefore, frequency of recessive allele (q) = 0.2.
Therefore, frequency of dominant allele (p) = 1 - 0.2 = 0.8.
Hence, the percentage of dominant alleles in a population = 0.8 * 100 = 80%.