In a population of 8000, 80 people can not recognize the taste of phenylthiocarbamide. Find out the number of homozygous tasters in given population

720

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6480

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7920

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 6480
Solution:
Answer C: $6480$
Genetic taster of PTC is TT or Tt.
Non taster are tt.
80 people out of 8000 is non tasters and their frequency is $0.01$ tt.
Weinburg equilibrium $q^{2} = 0.01$
So $q = 0.1$ , $p + q = 1, p = 1 - 0.1 = 0.9$
So $p^{2} = 0.9 \times 0.9 = 0.81 =$ Frequency of homozygous tasters. Now, since the total population is 8000 and total frequency of homozygous tasters is $0.81$
Total number of homozygous tasters is $x = 0.81 \times 8000 = 6480$

Suggest Corrections

Similar questions

Q. In case of taster and non-taster human beings, T is for dominance and t is for recessive gene. Which of the following would not be able to taste PTC (Phenylthiocarbamide)?

Q. The ability to taste the bitter chemical PTC is inherited as a simple dominant trait. In a population of 1000 biology students, 640 of them are PTC tasters. What proportion of this population are non-tasters?

Q. Frequency of a gene of PTC non taster is 0.4 than find out the number of heterogygous PTC taster in a population of 4,000:-

Question 112

The population of a village is 8000. Out of these, 80% are literate and of these literate people, 40% are women. Find the ratio of the number of literate women to the total population.

Q. 800 people dwell on an island, 16 are homozygous recessive for a trait that has only two different types of alleles in the population. Based on this information, find the number of heterozygotes in the population?

Join BYJU'S Learning Program