In a population, the frequency of the dominant allele A is 0.6 and that of the recessive allele a is 0.4. What would be the frequency of the heterozygous genotype in a random mating population at equilibrium?

0.36

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.48

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 0.48
Hardy-Weinberg equation is used calculate the frequency of occurrence of alleles in a population.
It has been given that the frequency of dominent allele 'p' = 0.6 and recessive allele 'q' = 0.4.
Applying the Hardy-Weinberg Equation, $p^{2} + 2 p q + q^{2} = 1$
The frequency of the heterozygous genotype (Aa) = 2pq
Substituting for p and q, we get
2pq = 2 x 0.4 x 0.6 = 0.48

Suggest Corrections

Similar questions

In a population, the frequency of the dominant allele A is 0.6 and that of the recessive allele a is 0.4. What would be the frequency of the heterozygous genotype in a random mating population at equilibrium?

Q. In a random mating population frequency of recessive allele is

0.5

. What is the frequency of dominant phenotypes in population?

Q. At a particular locus, frequency of allele A is

0.6

and that of allele a is

0.4

. What would be the frequency of heterozygotes in a random mating population at equilibrium?

Q. Frequency of 'A' allele is 0.6 and that of 'a' allele is 0.4. What would be frequency of heterozygotes in random mating population?

Q. At a particular locus, frequency of ‘A’ allele is 0.6 & that of ‘a’ is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?

Join BYJU'S Learning Program