Question

In a population with two alleles for a gene locus (P and p), the allele frequency of P is 0.7. What would be the frequency of heterozygotes if the population is in Hardy-Weinberg equilibrium?

• A. 0.49
• B. 0.42
• C. 0.21
• D. 0.09

Answer 1

The correct option is B 0.42

Frequency of allele P = 0.7 or 70%, Frequency of allele p = 0.3 or 30%.

From Hardy-Weinberg equilibrium : (p^2 + 2pq + q^2)

2pq (Heterozygous genotype) = 2 x 0.7 x 0.3 = 0.42 or 42%

So, the correct answer is '0.42'.