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Question
In a process a system does 140 J of work on the surrondings and only 40 J of heat is added to the system, hence change in internal energy is
In a process a system does 140 J of work on the surrondings and only 40 J of heat is added to the system, hence change in internal energy is
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Solution
The correct option is C -23.92 Cal
Given W = −140 J; q = 405
Δ E = q + W = 40 − 140 = −100 J(1cal = 4.18 J) = −23.92 Cal
-23.92 Cal
Given W = −140 J; q = 405
Δ E = q + W = 40 − 140 = −100 J(1cal = 4.18 J) = −23.92 Cal
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