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Byju's Answer
Standard XII
Physics
Poisson's Effect
In a process,...
Question
In a process, the pressure and volume of a given mass of gas increase. Then :
A
it is impossible
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B
the system does a positive work
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C
the temperature of the system must increase
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D
Δ
Q
=
Δ
U
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Solution
The correct options are
B
the temperature of the system must increase
C
the system does a positive work
Given that pressure and volume increase
P
2
>
P
1
and
V
2
>
V
1
From ideal gas law
P
1
V
1
T
1
=
P
2
V
2
T
2
P
1
V
1
T
1
=
P
2
V
2
T
2
T
2
=
P
2
V
2
P
1
V
1
T
1
(
P
2
P
1
>
1
,
V
2
V
1
>
1
)
Then temperature of the system will also increase
W
o
r
k
=
∫
2
1
P
d
V
Since
V
2
>
V
1
The system will do a positive work.
Suggest Corrections
0
Similar questions
Q.
The pressure p and volume V of an ideal gas both increase in a process.
(a) Such a process is not possible.
(b) The work done by the system is positive.
(c) The temperature of the system must increase.
(d) Heat supplied to the gas is equal to the change in internal energy.
Q.
Consider the following two statements and choose the correct answer :
A) If heat is added to a system its temperature must always increase
B) If positive work is done by a system in thermodynamic process its volume must increase.
Q.
A mass m of a perfect gas at pressure
p
1
and volume
V
1
undergoes an isothermal process. The final pressure is
p
2
and volume is
V
1
. The work done on the system is considered positive. If R is the gas constant and T is the temperature, then the work done in the process is
Q.
In a process on a system, the initial pressure and volume are equal to the final pressure and volume.
(a) The initial temperature must be equal to the final temperature.
(b) The initial internal energy must be equal to the final internal energy.
(c) The net heat given to the system in the process must be zero.
(d) The net work done by the system in the process must be zero.
Q.
Match the thermodynamic processes taking place in a system with the correct conditions.
In the table,
Δ
Q
is the heat supplied,
Δ
W
is the work done and
Δ
U
is the change in internal energy of the system.
Process
Condition
(i) Adiabatic
(A)
Δ
W
=
0
(ii) Isothermal
(B)
Δ
Q
=
0
(iii) Isochoric
(C)
Δ
U
≠
0
,
Δ
W
≠
0
,
Δ
Q
≠
0
(iv) Isobaric
(D)
Δ
U
=
0
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