Question

In a process the pressure of an ideal gas is proportional to square of the volume of the gas. If the temperature of the gas increases in this process, then work done by this gas:

• A. Is zero
  
• B. may be positive
  
• C. Is positive
  
• D. Is negative
  

Answer 1

The correct option is C Is positive


Given,
$P\propto V^2$
From the ideal gas equation,
$T\propto V^3$
i.e., if temperature increases, volume also increases hence work done will be positive.
Final answer: (𝒂)