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Question

In a projectile motion from a point of horizontal surface to another point on the same surface (Take a= acceleration and v= instantaneous velocity)

A
av=0 at maximum height
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B
av=0 only if angle of projection is 90
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C
a×v= constant every where in air
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D
None of these
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Solution

The correct options are
A av=0 at maximum height
C a×v= constant every where in air
At highest point
a=gˆj
v=ucosθ^iav=0
Option A is correct.

v=ucosθˆi+usinθˆjgtˆj
a=gˆj
a×v=ucosθg^k=constant
Option C is correct.

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