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Question

In a projectile motion the velocity

A
is always perpendicular to the acceleration
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B
is never perpendicular to the acceleration
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C
is perpendicular to the acceleration for one instant only
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D
is perpendicular to the acceleration for two instants.
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Solution

The correct option is C is perpendicular to the acceleration for one instant only
Projectile motion has 2 compounds horizontal & vertical μsinθ&μcosθ (4 is the initial velocity). Acceleration is only vertical in projectile motions.
So there is always some angle between velocity of acceleration. But at the
top most point of flight, only μcosθ (horizontal) in present but acceleration (g) in vertical, just st one instant.

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