In a projectile motion, velocity at maximum height is

$\frac{u c o s θ}{2}$

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$u c o s θ$

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$\frac{u s i n θ}{2}$

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None of these

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Solution

The correct option is B
$u c o s θ$

Only horizontal component of velocity $(u c o s θ)$ .

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In a projectile motion, velocity at maximum height is

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