In a public library, the librarian made the following observations in a particular week.

Days Mon. Tues. Wed. Thurs. Fri. Sat.

Newspaper readers 350 400 500 450 550 450

Magazine readers 200 450 300 250 100 50

(i) Draw a double bar graph choosing an appropriate scale.
(ii) On which day, the number of readers in the library was maximum?
(iii) What is the mean number of magazine readers per day?

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Solution

(i)

(ii) On Tuesday the number os readers in the library were maximum = 400 + 450 =850
(iii) Mean nnumber of magazine readers = $\frac{200 + 450 + 300 + 250 + 100 + 50}{6} = \frac{1350}{6} = 225$

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Question 82(iii)
In a public library, the following observations were recorded by the librarian in a particular week.
$\begin{matrix} Days & Mon & Tue & Wed & Thur & Fri & Sat Newspaper readers & 400 & 600 & 350 & 550 & 500 & 350 Magazine readers & 150 & 100 & 200 & 300 & 250 & 200 \end{matrix}$
What is the mean number of magazine readers?

The following table shows the daily production of T. V. sets in an industry for $7$ days of a week:

$\begin{matrix} Days & Monday & Tuesday & Wednesday & Thursday & Friday & Saturday & Sunday Number of TV sets & 300 & 400 & 150 & 250 & 100 & 350 & 200 \end{matrix}$

Represent the above information by a pictograph.

Question 82(ii)
In a public library, the following observations were recorded by the librarian in a particular week.
$\begin{matrix} Days & Mon & Tue & Wed & Thur & Fri & Sat Newspaper readers & 400 & 600 & 350 & 550 & 500 & 350 Magazine readers & 150 & 100 & 200 & 300 & 250 & 200 \end{matrix}$
On which day, the number of readers in the library was maximum?

Q. The following table shows the maximum temperature of a city on each day of a week. Represent the given data by a line graph: [3 MARKS]

\begin{matrix} Days & M o n . & T u e . & W e d . & T h u r . & F r i . & S a t . & S u n . Max.Temp.(in °C) & 34 & 35 & 37 & 38 & 41 & 39 & 36 \end{matrix}

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Days	Mon.	Tues.	Wed.	Thurs.	Fri.	Sat.
Newspaper readers	350	400	500	450	550	450
Magazine readers	200	450	300	250	100	50

(i) (ii) On Tuesday the number os readers in the library were maximum = 400 + 450 =850 (iii) Mean nnumber of magazine readers = 200+450+300+250+100+506=13506=225

(i)

(ii) On Tuesday the number os readers in the library were maximum = 400 + 450 =850
(iii) Mean nnumber of magazine readers = $\frac{200 + 450 + 300 + 250 + 100 + 50}{6} = \frac{1350}{6} = 225$