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Capacitor in an AC Circuit

In a pure cap...

Question

In a pure capacitive circuit if the frequency of ac source is doubled, then its capacitive reactance will be

A

remains same

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B

doubled

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C

halved

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D

zero

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Solution

The correct option is D halved
Capacitive reactance, $X_{c} = \frac{1}{2 π ν C}$

We can see that $X_{c} \propto \frac{1}{ν}$ ,

if $ν$ is doubled, $X_{c}$ will be halved

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