In a quadratic function f(x) = ax2 + bx + c. It is known that f(1) = f(4) and f(2) = 0, then what is the second root of the expression?
option (a)
Solution: Let 'a' be the second root with '2' being the first root.
Then the given equation can be written as: (x-2)(x-a)=0--------------(1)
Now, we know that f(1)=f(4)-------------------(2)
Using (2) in (1):
(1-2)(1-a)=(4-2)(4-a)
Therefore, a=3 is the correct answer.