Question

In a quadrilateral ABCD

$AB+BC+CD+DA>2AC$

• A. True
• B. False

Answer 1

The correct option is A True

In $△ABC$,

$AB+BC>AC$ ( Sum of any two sides of a triangle is greater than the third side)

In $△ACD$,

$CD+DA>AC$ ( Sum of any two sides of a triangle is greater than the third side)

Adding these inequations, we get,

$AB+BC+CD+DA>2AC$