Question

In a quadrilateral ABCD AB || CD and $AD\perp AB$ Also AB = 16 cm, DC = BC = 10 cm The area of the quadrilateral is

• A. 26 $c{m}^2$
• B. 54 $c{m}^2$
• C. 52 $c{m}^2$
• D. 104 $c{m}^2$

Answer 1

The correct option is D 104 $c{m}^2$

$BE=16-10=6cm$
$h^2+6^2={10}^2$
$\Rightarrow h=8$
Area of $ABCD=\frac{1}{2}(16+10)\times 8c{m}^2$
$=104c{m}^2$