Question

In a quadrilateral ABCD, AC = 15 cm. The perpendiculars drawn from B and D respectively to AC measure 8.2 cm and 9.1 cm. Find the area of the quadrilateral

Answer 1

Area of quadrilateral = $\frac{1}{2}d(h_1+h_2)$
= $\frac{1}{2}\times 15(8.2+9.1)c{m}^2$
= $\frac{1}{2}\times 15\times 17.3c{m}^2=129.75c{m}^2$