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Area of a Parallelogram

In a quadrila...

Question

In a quadrilateral ABCD, AC = 15 cm. The perpendiculars drawn from B and D respectively to AC measure 8.2 cm and 9.1 cm. Find the area of the quadrilateral

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Solution

Area of quadrilateral = $\frac{1}{2} d (h_{1} + h_{2})$
= $\frac{1}{2} \times 15 (8.2 + 9.1) c m^{2}$
= $\frac{1}{2} \times 15 \times 17.3 c m^{2} = 129.75 c m^{2}$

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Area of a Parallelogram

Standard IX Mathematics

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