In a quadrilateral $A B C D$ , $∠ D = 90^{o}$ & $∠ A = ∠ B = ∠ C$ , find $∠ A$ .

90

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100

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110

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80

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Solution

The correct option is C $90$
In quadrilateral $A B C D$ ,
$∠ A + ∠ B + ∠ C + ∠ D = 360$
Let $∠ A = ∠ B = ∠ C = x,$
Therefore, $x + x + x + 90 = 360$
$\Rightarrow 3 x = 270$
$\Rightarrow x = 90$
Therefore, $∠ A = 90^{o}$

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