Question

In a quadrilateral ABCD, AO & DO are angle bisectors of $\angle$A, and $\angle$D and given that $\angle C={105}^o,\angle B={70}^o$, then the $\angle AOD$ is

• A. ${67.5}^o$
• B. ${77.5}^o$
• C. ${87.5}^o$
• D. ${99.75}^o$

Answer 1

Answer: (C)

${87.5}^o$

Using previous questions result
$2\angle AOD=\angle C+\angle B$
$2\angle AOD={175}^O$
$\angle AOD={87.5}^o$