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Question

In a quadrilateral ABCD, ∠B = 90°, AD2 = AB2 + BC2 + CD2, prove that ∠ACD = 90°.

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Solution

In order to prove angle it is enough to prove that .

Given,

.....(1)

Since, so applying Pythagoras theorem in the right angled triangle ABC, we get

.....(2)

From (1) and (2), we get

Therefore, angle . (Converse of pythagoras theorem)


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