In a quadrilateral ABCD - - B -90- - If AD 2- AB 2- BC 2- CD 2 then prove that - ACD -90-

In quadrilateral ABCD, we have ∠B = 90° So, nbsp; nbsp; (Pythagoras theorem) and nbsp; nbsp; nbsp; (Given) So, Hence, ∠ACD = 90° nbsp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Pythagoras Theorem

In a quadrila...

Question

In a quadrilateral ABCD, ∠B = 90°. If AD² = AB² + BC² + CD² then prove that ∠ACD = 90°.

Open in App

Solution

Suggest Corrections

Similar questions

A B C D

∠ B = 90

{A D}^{2} = {A B}^{2} + {B C}^{2} + {C D}^{2}

∠ A C D = 90^{0}

A B C D ∠ B = 90^{o}

A D^{2} = A B^{2} + B C^{2} + C D^{2}

∠ A C D = 90^{o}

A B C D

∠ A B C = 90^{o}

{A D}^{2} = ({A B}^{2} + {B C}^{2} + {C D}^{2})

∠ A C D = 90^{o}

∠ B = 90^{\circ} a n d A D^{2} = A B^{2} + B C^{2} + C D^{2} . t h e n ∠ A C D i s

Join BYJU'S Learning Program