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Conditional Probability

In a quadrila...

Question

In a quadrilateral ABCD, which is not a trapezium, it is known that $∠$ DAB = $∠$ ABC = $60^{0}$ . Moreover, $∠$ CAB = $∠$ CBD. Then,

A

AB = BC + CD

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B

AB = AD + CD

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C

AB = BC +AD

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D

AB = AC + AD

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Solution

The correct option is D
AB = AC + AD

AB = AC + AD

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Similar questions

Q. In a quadrilateral ABCD, which is not a trapezium, it is known that

∠

= ∠

= 60^{o}

∠

= ∠

Q. In the given figure,

A B C D

is a cyclic quadrilateral in which

∠ C A D = 25^{o}, ∠ A B C = 50^{o}

∠ A C B = 35^{o}

∠ C B D

∠ D A B

∠ A D B

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Q. In the given figure,

A B C D

is a cyclic quadrilateral in which

∠ C A D = 25^{o}

∠ A B C = 50^{o}

∠ A C B = 35^{o}

∠ D A B

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A D = B C

∠ D A B = ∠ C B A

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∠ A D B + ∠ D A B = 120^{o}

∠ A B C + ∠ B D A = 145^{o}

. Find the value of

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