In a quadrilateral, half of the product of the sum of the lengths of parallel sides and the distance between them gives the area of a ______.

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Solution

In a quadrilateral, half of the product of the sum of the lengths of parallel sides and the parallel distance between them gives the area of a trapezium.

Area of trapezium $A B C D = \frac{1}{2} \times$ (Sum of parallel sides) $\times$ perpendicular distance between them
$= \frac{1}{2} \times (b_{1} + b_{2}) \times h$

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In a quadrilateral, half of the product of the sum of the lengths of parallel sides and the distance between them gives the area of a ______.

In a quadrilateral, half of the product of the sum of the lengths of parallel sides and the parallel distance between them gives the area of a trapezium.Area of trapezium ABCD=12× (Sum of parallel sides) × perpendicular distance between them=12×(b1+b2)×h