In a race of 200 m run, A beats S by 20 m and N by 40 m. Ifs S and N are running race of 100 m with exactly same speed as before, then by how metres will S beat ?

11.11 m

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Solution

The correct option is B $11.11 m$
When A runs 200 m
S runs 180 m
N runs 160 m
When S run 100 m, N will run= $100 \times \frac{160}{180} = 88.89$
i.e S will beat N by $(100 - 88.89) = 11.11$ m

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In a race of 200 m run, A beats S by 20 m and N by 40 m. Ifs S and N are running race of 100 m with exactly same speed as before, then by how metres will S beat ?

The correct option is B 11.11 mWhen A runs 200 m S runs 180 m N runs 160 mWhen S run 100 m, N will run=100×160180=88.89i.e S will beat N by (100−88.89)=11.11 m

The correct option is B $11.11 m$
When A runs 200 m
S runs 180 m
N runs 160 m
When S run 100 m, N will run= $100 \times \frac{160}{180} = 88.89$
i.e S will beat N by $(100 - 88.89) = 11.11$ m