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Question

In a race where 12 cars are running, the chance that car A will win is 18, that B will win is 110 and that C will win is 16. Find the chance that one of them will win.

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Solution

The correct option is **D**

47/120

Required probability = P(X)+P(Y)+P(Z) (all the events are mutually exclusive).

= 16 + 110 + 18 = 47120

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