In a random mating population, frequency of disease causing recessive allele is 80%. What would be the frequency of carrier individual in population?
A
64%
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B
32%
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C
16%
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D
100%
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Solution
The correct option is B 32% According to the question, the genotype frequency of recessive allele is (q) = (80% or 0.8). Since p+q=1; thus the frequency of dominant allele= p= 1-0.8= 0.2. The frequency of the carrier individual= 2pq= 2 X 0.8 X 0.2= 0.32 or 32%. The correct option is B.