In a reaction- 2 A - Products- the concentration of A decreases from 0-5 mol L -1 to 0-4 mol L -1 in 10 minutes- Calculate the rate during this interval-

Average rate = 0.005 mol L−1 min−1 = 5 × 10−3 M min−1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factors Affecting Rate Constant

In a reaction...

Question

In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L⁻¹ to 0.4 mol L⁻¹ in 10 minutes. Calculate the rate during this interval?

Open in App

Solution

Suggest Corrections

Similar questions

2 A \to P r o d u c t s

0.5 m o l L^{- 1}

0.4 m o l L^{- 1}

2 A \to P r o d u c t s

A

0.5 m o l l i t r e^{- 1}

0.4 m o l l i t r e^{- 1}

10

2 H I \to H_{2} + I_{2}

H I

0.5 m o l L^{- 1}

0.4 m o l L^{- 1}

10

In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L^-1 to 0.4 mol L^-1 in 10 min. The rate during this interval will be

R ⟶ P

2 A ⟶ P r o d u c t s

A

0.5

0.4 m o l L^{- 1}

Join BYJU'S Learning Program