In a reaction $A + B ⇌ C + D$ , the concentration of $A, B, C$ and $D$ (in moles/litre) are $0.5, 0.8, 0.4$ and $1.0$ respectively. The equilibrium constant is

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Solution

$K e q = \frac{[C] [D]}{[A] [B]}$

$K e q = \frac{1.0 \times 0.4}{0.8 t i m e s 0.5}$
= 1.0

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In a reaction A+B⇌C+D, the concentration of A,B,C and D (in moles/litre) are 0.5,0.8,0.4 and 1.0 respectively. The equilibrium constant is

Keq=[C][D][A][B] Keq=1.0×0.40.8 times0.5= 1.0

In a reaction $A + B ⇌ C + D$ , the concentration of $A, B, C$ and $D$ (in moles/litre) are $0.5, 0.8, 0.4$ and $1.0$ respectively. The equilibrium constant is

$K e q = \frac{[C] [D]}{[A] [B]}$

$K e q = \frac{1.0 \times 0.4}{0.8 t i m e s 0.5}$
= 1.0