Question

In a reaction $A\to$ products, the rate is doubled when the concentration of A is increased 4 times. If 50% of the reaction occurs in 1414 sec , how long would it takes for the completion of 75% reaction.

• A. 4242sec
• B. 2825 sec
• C. 2414 sec
• D. 2121 sec

Answer 1

The correct option is C

2414 sec

Order= $\frac{1}{2}$

First $t\frac{1}{2}=1414sec;$

therefore second $t\frac{1}{2}$
$(t\frac{1}{2}\propto \frac{1}{a^{n-1}})=\frac{1414}{\sqrt{2}}=1000sec$

$\therefore$ total time for 75% reaction is 1414+1000=2414 sec