In a reaction, a substance undergoes decomposition which is catalyzed in the presence of finely divided nickel. If there are enough sites on the surface of catalysts so that 20 molecules of substance react per second, the rate of reaction for a 1.0M solution is:

3.34 \times 10^{- 23} m o l L^{- 1} s^{- 1}

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3.14 \times 10^{- 23} m o l L^{- 1} s^{- 1}

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3.68 \times 10^{- 23} m o l L^{- 1} s^{- 1}

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Solution

The correct option is A $3.34 \times 10^{- 23} m o l L^{- 1} s^{- 1}$
20 Molecules reacts in
1 s $\Rightarrow$ 1 mol of molecules react is $[\frac{1}{20} \times 6 \times 10^{23}] s$
$\Rightarrow$ Rate of reaction for 1 M solution.
= $\frac{1}{\frac{1}{20} \times 6 \times 10^{23}} = 3.34 \times 10^{- 23} m o l L^{- 1} s^{- 1}$

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In a reaction, a substance undergoes decomposition which is catalyzed in the presence of finely divided nickel. If there are enough sites on the surface of catalysts so that 20 molecules of substance react per second, the rate of reaction for a 1.0M solution is:

The correct option is A 3.34×10−23molL−1s−120 Molecules reacts in1 s ⇒ 1 mol of molecules react is [120×6×1023]s⇒ Rate of reaction for 1 M solution.= 1120×6×1023=3.34×10−23molL−1s−1