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Question

In a reaction excess of H2O2 is added to 0.1 mole of acidfied KMnO4 solution. Then the STP volume of O2 liberated is?

A
5.6 lit
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B
6.6 lit
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C
11.2 lit
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D
22.4 lit
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Solution

The correct option is A 5.6 lit
Equivalents of H2O2 needed to react completely
with 0.1 mole kMnO4=0.1×nf(nf of kMnO4=5)=0.5
Now, H2O2H2O+1/2O2 1 equivalent H2O2 produce 2242=112 L O2 0. 5 equivalent H2O2 will produce 0.5×112=5.6L O2 So, A ) 5.6 litre is correct answer.

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