In a reaction if the concentration of reactant A is tripled, the rate of reaction becomes twenty seven times. What is the order of the reaction?

Open in App

Solution

Rate of any elementary reaction can be represented as
$r = k [A]^{n}$
After changing concentration to its triple value A = 3A, r becomes 27r
$27^{r} = k [3 A]^{n} \frac{r}{27^{r}} = \frac{k [A]^{n}}{k [3 A]^{n}} \frac{1}{27} = {[\frac{1}{3}]}^{n} \Rightarrow {[\frac{1}{3}]}^{3} = {[\frac{1}{3}]}^{n}$

Hence, n=3

Order of reaction is three.

Suggest Corrections

Similar questions

Q. When the concentration of a reactant of first order reaction is doubled, the rate becomes ________ times, but for ___________ order reaction, the rate remains same.

Q. A reaction is second order with respect to a reactant. If the concentration of reactant is doubled the rate of reaction becomes :

Q. For a second order reaction rate at a particular time is

X

. If the initial concentration is tripled, the rate will become:

If a reaction has the experimental rate expression rate = $K [A]^{2} [B]$ , if the concentration of A is doubled and the concentration of B is halved, the what happens to the reaction rate:-

Q. The half-life period of a reaction becomes 16 times when reactant concentration is halved. The order of reaction is ______.

Join BYJU'S Learning Program

In a reaction if the concentration of reactant A is tripled, the rate of reaction becomes twenty seven times. What is the order of the reaction?

Rate of any elementary reaction can be represented as r=k[A]n After changing concentration to its triple value A = 3A, r becomes 27r 27r=k[3A]nr27r=k[A]nk[3A]n127=[13]n⇒[13]3=[13]n Hence, n=3 Order of reaction is three.