In a reaction involving one single reactant- the fraction of the reactant consumed may be defined as f-1-C-C0where C0 and C are the concentrations of the reactant at the start and after time t- For a first order reaction the remaining amount is -

The correct option is D df/dt=k(1 f) Fraction of reactant consumed #160; f=(1 C/C_0) For a reaction : df/dt=k(1 f) #160; (Remaining amount) ...

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Byju's Answer

Standard XII

Chemistry

Factors Affecting Rate of Reaction

In a reaction...

Question

In a reaction involving one single reactant, the fraction of the reactant consumed may be defined as $f = (1 - \frac{C}{C_{0}})$
where $C_{0}$ and C are the concentrations of the reactant at the start and after time t. For a first order reaction the remaining amount is :

\frac{d f}{d t} = k (1 - f)

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- \frac{d f}{d t} = k f

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- \frac{d f}{d t} = k (1 - f)

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\frac{d f}{d t} = k f

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Solution

The correct option is D $\frac{d f}{d t} = k (1 - f)$
Fraction of reactant consumed $f = (1 - \frac{C}{C_{0}})$
For a reaction : $\frac{d f}{d t} = k (1 - f)$ (Remaining amount).

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In a reaction involving one single reactant, the fraction of the reactant consumed may be defined as f=(1−CC0)where C0 and C are the concentrations of the reactant at the start and after time t. For a first order reaction the remaining amount is :

The correct option is D dfdt=k(1−f)Fraction of reactant consumed f=(1−CC0)For a reaction : dfdt=k(1−f) (Remaining amount).

In a reaction involving one single reactant, the fraction of the reactant consumed may be defined as $f = (1 - \frac{C}{C_{0}})$
where $C_{0}$ and C are the concentrations of the reactant at the start and after time t. For a first order reaction the remaining amount is :

The correct option is D $\frac{d f}{d t} = k (1 - f)$
Fraction of reactant consumed $f = (1 - \frac{C}{C_{0}})$
For a reaction : $\frac{d f}{d t} = k (1 - f)$ (Remaining amount).