Question

In a reaction turbine the enthalpy drop in a moving blade is $32kJ/kg$ and degree of reaction is $0.4$. Then the enthalpy drop in fixed blade will be :

• A. $48kJ/kg$
• B. $80kJ/kg$
• C. $36kJ/kg$
• D. $56kJ/kg$

Answer 1

The correct option is A $48kJ/kg$

Degree of reaction DOR $=\frac{(\Delta h{)}_{moving}}{(\Delta h{)}_{moving}+(\Delta h{)}_{fixed}}$
$=0.4=\frac{32}{32+(\Delta h{)}_{fixed}}$
$\Rightarrow \Delta h_{fixed}=48kJ/kg$